Treehouse puzzle bug

pixel_player108961443

The treehouse puzzle has a problem. The information given is incomplete: we have three equations in four unknowns. Despite this, it can approximately be solved, as the loot in the four houses can be broken down mostly into the combinations with known values, adding to 66, with one object left over. Assuming all values are greater than or equal to one, the one left-over object must have value 1, 2, 3, or 4 since one combination it is in adds to 5. The other it's in has it with two copies of another object adding to 10, so it must be an even number: 2 or 4. The total then comes to either 68 or 70. However, nothing triggers when either of those is input. In case the "example objects" count, adding an extra 21, I also tried 89 and 91. Nothing triggered in response to those either.

So, 2 things are broken: missing information; and the correct answer (whichever of the 4 possibilities I narrowed it down to is actually it) doesn't trigger anything when input.

Sandra_s_Quest

pixel_player108961443 I think you're over thinking it & give the creators too much credit. It's much simpler.

The value for the chairs is 3.
The value for the eggs is 2.
The value for the apples is 4.

You have 10 of each in all 4 treehouses, including the objects in the equations, so that makes a total of 90.

gamemaster

pixel_player108961443
Join the club, we already mentioned here
https://forum.pixelfederation.com/diggysadventure/d/193262-bandit-forest-walkthrough-article/2

pixel_player108961443 I also tried 89 and 91

🤣 that was so close 🤣
I got other numbers until the chairs were pointed out to be equal, and not 2 separate things.
Stupid puzzle.

pixel_player108961443

Sandra_s_Quest

Under that valuation, and counting the example ones, I get 89. I can't even have missed an object, since the hypothetical missing object would have to have a value of 1, not 2, 3, or 4. And who keeps moving my threads???

CloudSwift2

pixel_player108961443 There are 10 of each item and all the item values are integers so the answer has to be a multiple of 10. If you came up with a value like 89, you must have done something like count one extra chair and missed one apple or one extra eggs and missed a chair or some other combination of overcounting one item and undercounting another.

CloudSwift2

Yes, it is three equations with 3 unknowns.
2 chairs = 6 so a chair is 3
chair plus pile of eggs (or nuggets or whatever they are) = 5, 5 - 3 = 2 so a pile is 2
2 apples plus a pile = 10, so an apple is 4.

Though there are cases where the requirement that all values are positive integers adds enough of a constraint that there is only one solution even in a case like 3 equations with 4 unknowns.

But in this case it is just 3 unknowns because it doesn't matter which way the chair faces.

AllMenAreIslands

It's Pixel Math.

At least now we can understand how they're doing the "calculations" to come up with equipment values.